## What does the de Broglie wavelength depend on?

The De Broglie wavelength doesn’t directly depend on the charge; however, it depends on the momentum. Therefore, if an electric field accelerates a charged particle, then the momentum acquired would depend on the charge.

### What determines the value of the de Broglie wavelength for an electron?

The velocity of the electron determines the de Broglie wavelength of the electron.

What is the de Broglie wavelength associated with Nth Orbital?

De – Broglie wavelength of electron in nth orbit of H – atom is (3.18pi)A .

Which is the correct relation between de Broglie wavelength of an electron in the nth Bohr orbit and radius of the orbit r?

λ=nh2πR.

## Does de Broglie wavelength depend on velocity?

the de-Broglie wavelength is inversely proportional to the mass of the particle and its velocity but is independent of the nature of the particle.

### Does de Broglie wavelength depend on frame of reference?

Yes. The De broglie wavelength depends on the frame of reference and the usual relativity length contraction formula applies. In an initial reference frame attached to the particle, the wavelenth would be it’s proper length.

What is the de Broglie wavelength of an electron?

Applications of de Broglie Waves 10 eV electrons (which is the typical energy of an electron in an electron microscope): de Broglie wavelength = 3.9 x 10-10 m. This is comparable to the spacing between atoms.

What is de Broglie’s relation?

De Broglie proposed that as light exhibits both wave-like and particle-like properties, matter to exhibit wave-like and particle-like properties. This nature was described as dual behaviour of matter. On the basis of his observations, de Broglie derived a relationship between wavelength and momentum of matter.

## What is the relation between potential difference and de Broglie wavelength?

The De Broglie wavelength is inversely proportional to the square root of the potential.

### How do you find the wavelength of an electron in an orbit?

Apply the de Broglie wave equation λ=hmv λ = h m v to solve for the wavelength of the moving electron.

What is the relation between de Broglie wavelength and radius?

Since the circumference of a cirle is 2pi times the radius, the general formula relating deBroglie wavelength to orbit radius is just the following: lambda(n) = 2pi x r(n) / n, where lambda(n) is the deBroglie wavelength, pi is just 3.1416, r(n) is the radius of the nth orbit, and n = 1, 2, 3., etc.

Is De Broglie’s relation applicable to an electron?

Solution : No, it applies to all moving microscopic particles.